y+10/4y^2+3y-1

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Solution for y+10/4y^2+3y-1 equation: 


y in (-oo:+oo)

(10/4)*y^2+y+3*y-1 = 0

5/2*y^2+4*y-1 = 0

DELTA = 4^2-(-1*5/2*4)

DELTA = 26

DELTA > 0

y = (26^(1/2)-4)/(2*5/2) or y = (-26^(1/2)-4)/(2*5/2)

y = (26^(1/2)-4)/5 or y = (-(26^(1/2)+4))/5

y in { (-(26^(1/2)+4))/5, (26^(1/2)-4)/5 }

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